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Al^(3+)(aq) + 3e^(-) rightarrow Al(s) E^...

`Al^(3+)(aq) + 3e^(-) rightarrow Al(s)` `E^(@) = -1.66V`
`Cu^(2+)(aq) + 2e^(-) rightarrow Cu(s)` `E^(@) = +0.34V`
What voltage is produced under standard conditions by combining the half-reactions witih these standard Electrode Potential?

A

1.32 V

B

2.00 V

C

2.30 V

D

4.34 V

Text Solution

Verified by Experts

The correct Answer is:
B
The cell will be
`Al (s) |Al^(3+) (aq.)|| Cu^(2+) (aq.) | Cu(s)`
`E_("Cell")^(@) = E_("Cathode")^(@) - E_("Anode")^(@)`
`= E_(Cu^(2+)//Cu)^(@) - E_(Al^(3+) // Al)^(@)`
`= +0.34 - (- 1.66) = + 2.00 V`
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