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(10Cl^(-)(aq) + 2MnO(4)^(-)(aq) + 16H^(+...

`(10Cl^(-)(aq) + 2MnO_(4)^(-)(aq) + 16H^(+)(aq) rightarrow 5Cl_(2)(g) + 2Mn^(2+) + 8H_2O)(l)`
The value of `E^(@)` for this reaction at `25^(@)C` is 0.15 V. What is the value of K for this reaction?

A

`2.4 xx 10^(25)`

B

`4.9 xx 10^(12)`

C

`1.2 xx 10^(5)`

D

`3.4 xx 10^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K = " antilog " [(nE^(@))/(0.059)]`
`= " antilog " [(10 xx 0.15)/(0.059)]`
`~~ 2.4 xx 10^(25)`
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