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For the following cell, Zn(s)|ZnSO(4)(...

For the following cell,
`Zn(s)|ZnSO_(4)(aq)||CuSO_(4)(aq)||Cu(s)`
When the concentration of `Zn^(2+)` is 10 times the concentration of `Cu^(2+)`, the expression for `DeltaG`
(in J `"mol"^(-1)`)
[F is Faraday constant, R is gas constant] T is temperaure, `E^(@)("cell")=1.1V`

A

`2.303 RT + 1.1 F`

B

`2.303 RT - 2.2F`

C

`1.1F`

D

`-2.2 F`

Text Solution

Verified by Experts

The correct Answer is:
B
We know, `Delta G = Delta G^(@) + 2.303 RT "log"_(10)Q`
`= - nFE^(@) + 2.303RT " log"_(10)Q`
`= -2 xx F 1.10 + 2.303 RT " log " ([Zn^(2+)])/([Cu^(2+)])`
`= - 2.2F + 2.303 RT "log"_(10) 10`
`= - 2.2F + 2.303 RT`
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