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A hydrogen electrode X was placed in a b...

A hydrogen electrode X was placed in a buffer solution of sodium acetate and acetic acid in the ratio `a:n` and another hydrogen electode Y was placed in a buffer solution of sodium acetate and acetic acid in the ratio `b:a`. If reduction potential values for two cells are found to be `E_(1)` and `E_(2)` respectively w.r.t standard hydrogen electrode, the `pK_(a)` value of the acid can be given as:

A

`(E_(1) + E_(2))/(0.118)`

B

`(E_(2) - E_(1))/(0.118)`

C

`(-E_(1) + E_(2))/(0.118)`

D

`(E_(1) - E_(2))/(0.118)`

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The correct Answer is:
A
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