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Assertion (A): For a Daniell cell : Zn...

Assertion `(A):` For a Daniell cell `:`
`Zn|Zn^(2+)||Cu^(2+)|Cu` with `E_(cell)=1.1V`, the application of opposite potential greater than `1.1V` results into the flow of electron from cathod to anode. Reason `(R):` Zn is deposited at anode and Cu is dissolved at cathode

A

If both (A) and (R) are correct, and (R) is the correct explanation of (A).

B

If both (A) and (R) are correct, but (R) is not the correct explanation of (A).

C

If (A) is correct, but (R) is incorrect

D

If (A) is incorrect, but (R) is correct.

Text Solution

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The correct Answer is:
B
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For the Daniell cell Zn| Zn^(2+) || Cu^(2+) | Cu with The questions consist of two statements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses : E_(cell) = 1.1 V , the application of oposite potential grater than 1.1 V results into folow of electron from Cu to Zn . Zn is deposited at anode and Cu is deposited at cathode .

In the cell, Zn|Zn^(2+)"||"Cu^(2+)|Cu ________.

For the cell given, below Zn|Zn^(2)||Cu^(2+)|Cu,(E_(cell)-E_(cell)^(@)) is -0.12 V. it will be when

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