Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation :
`kappa=c xx l/A`
where, `c=1//R` is the conductance and `l//A` is the cell constant. Molar conductance `(Lambda_(m))` and equivalence conductance `(Lambda_(e))` of an electrolyte solution are calculated using the following similar relations :
`Lambda_(m)= kappa xx 1000/M`
`Lambda_(e)= kappa xx 1000/N`
Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration :
`Lambda_(m)=Lambda_(m)^(@)-b sqrt(c)`
where, `Lambda_(m)^(@)=` molar conductance at infinite dilution
c= concentration of the solution
b= constant
The degrees of dissociation of weak electrolytes are calculated as :
`alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@)`
For which of the following electrolytic solution `Lambda_(m)` and `Lambda_(e)` are equal ?

Options

A. `BaCl_(2)`
B. `KCl`
C. `Al_(2)(SO_(4))_(3)`
D. `CaCl_(2)`

Answer

B