At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated.
the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions.
`A_(x)B_(y) rarr xA^(y+)+yB^(x-)`
`Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@)`
where, x and y are the number of cations and anions respectively.
The degree of ionisation `'alpha'` of weak electrolyte can be calculated as :
`alpha=Lambda_(m)/Lambda_(m)^(@)`
The ionic conductances of `Al^(3+)` and `SO_(4)^(2-)` ions at infinite dilution are x and y `ohm^(-1) cm^(2) mol^(-1)` respectively. If Kohlrausch's law is valid then molar conductance of aluminium sulphate at infinite dilution will be :

Options

A. 3x + 2y
B. 3y + 2x
C. 2x + 2y
D. 3x + 3y

Answer

B