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For each of the following reactions, exp...

For each of the following reactions, express the given rate of change of concentration of the reactants or Products in that reaction:
(a) `H_(2)O_(2) + 2H^(o+) + 3I^(ɵ) rarr I_(3)^(ɵ) + 2H_(2)O`, `(-d[I^(ɵ)])/(d t) = ?`, `(-d[H^(o+)])/(d t) ? `
(b) `16H^(o+) + 2MnO_(4)^(ɵ) + 10I^(ɵ) rarr 2Mn^(2+) + 8H_(2)O + 5I_(2)`, `(-d[MNO_(4)^(ɵ)])/(d t) = ?`
( c) `4NH_(3) + 5O_(2) rarr 4NO_(2) + 6H_(2)O` , `(-d[NH_(3)])/(d t) = ?`

Text Solution

Verified by Experts

We have,
(a) `H_(2)O_(2)+2H^(+)+3I^(-)rarrI_(3)^(-)+2H_(2)O`
The equantity in this case is :
`-(d[H_(2)O_(2)])/(dt)=-(1)/(2)(d[H^(+)])/(dt)=-(1)/(3)(d-[I^(-)])/(dt)=(d[I_(3)^(-)])/(dt)=(1)/(2)(d[H_(2)O])/(dt)`
So,
`-(d[I^(-)])/(dt)=-3(d[H_(2)O_(2)])/(dt)=-(2)/(3)(d[H^(+)])/(dt)=3(d[I_(2)^(-)])/(dt)=(3)/(2)(d[H_(2)O])/(dt)`
and `-(d[H^(+)])/(dt)=-2(d[H_(2)O_(2)])/(dt)=(2)/(3)(d[I^(-)])/(dt)=2(d[I_(3)^(-)])/(dt)=(d[H_(2)O])/(dt)`
(b) `16H^(+)=2MnO_(4)^(-) +10I^(-)rarr2Mn^(2+)+8H_(2)O+5I_(2)`
The equality in this case :
`(1)/(16)(d[H^(+)])/(dt)=(1)/(2)(d[MnO_(4)^(-)])/(dt)=-(1)/(4)(d[I_(2)])/(dt)`
`(1)/(16)(d[H^(+)])/(dt)=(1)/(2)(d[MnO_(4)^(-)])/(dt)=-(1)/(10)(d[I^(-)])/(dt)`
`=(1)/(2)(d[Mn^(2+)])/(dt)=(1)/(8)(d[H_(2)O])/(dt)=(1)/(5)(d[I_(2)])/(dt)`
So, `-(d[MnO_(4)^(-)])/(dt)=-(1)/(8)(d[H^(+)])/(dt)=-(1)/(5)(d[I^(-)])/(dt)`
`=(d[Mn^(2+)])/(dt)=(1)/(4) (d[H_(2)O])/(dt)=(2)/(5) (d[I_(2)])/(dt)`
(c) `4NH_(3)+7\O_(2)rarr4NO+_(2)=6H_(2)O`
The equality in this case is :
`-(1)/(4)(d[NH_(3)])/(dt)=-(1)/(5)(d[O_(2)])/(dt)=(1)/(6)(d[H_(2)O])/(dt)`
So, `-(d[Nh_(3)])/(dt)-(4)/(5)(d[O_(2)])/(dt)=(d[NO_(2)])/(dt)=(2)/(3)(d[H_(2)O])/(dt)`
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