A second order reaction in which in both the reactants have same conentratio, is `20%` completed in 500 seconds. How much time it will take for `60%` completion?

Explanation

To solve the problem step by step, we will use the formula for a second-order reaction where both reactants have the same concentration.

### Step 1: Understand the formula for a second-order reaction
For a second-order reaction where both reactants have the same concentration, the rate constant \( K \) can be expressed as:
\[ K = \frac{1}{T} \cdot \frac{X}{A \cdot (A - X)} \]
where:
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