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At a certain temperature the half change...

At a certain temperature the half change periof for the catalystic decompoistion of ammonia was found as follows:
`|{:("Pressure (Pa)",6667,13333,26666),("Half life periof in hours",3.52,1.92,1.0):}|`
Calculate the order of reaction.

Text Solution

Verified by Experts

`((t_(1//2))_(1))/((t_(1//2))_(2))=((a_(2))/(a_(1)))^(n-1)` where, n is order of reaction
From the given data,
`(3.25)/(1.92)=((13333)/(6667))^(n-1)" " (a prop "initial pressure")`
`log .(3.52)/(1.92)=(n-1)log2=0.3010xx(n-1)`
`0.2632=0.30120xx(n-1)`
`n=1.87~~2`
Similar calculations are made between first and third observation. n comes equal to `1.908(~~2)`
Thus, the reaction is of second. order.
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