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Pseudo first order rate for the reaction...

Pseudo first order rate for the reaction
`A + B rarr P`
when studied in `0.1 M` of `B` is given by
`-(d[A])/(dt) = k[A]`
where `k = 1.85 xx 10^(4)s^(-1)`. Calculate the value of second order rate constant.

Text Solution

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`A+BrarrP`
`-(d[A])/(dt)=k[A]`
`-(d[A])/(dt)=1.85xx10^(4)xx[A]" "....(i)`
Assuming the reaction to be of second order,
`-(d[A])/(dt)=k'[A][B]`
`-(d[A])/(dt)=k'[A][\0.1]" " .....(ii)`
Dividing eq. (i) by eq. (ii), we get
`1=(1.85xx10^(4))/(k'[0.1])`
`k'=1.852xx10^(5)` litre `"mol"^(-1) sec^(-1)`
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