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The rate constant of a reaction is 1.5 x...

The rate constant of a reaction is `1.5 xx 10^(7)s^(-1)` at `50^(@)C` and `4.5 xx 10^(7) s^(-1)` at `100^(@)C`. Evaluate the Arrhenius parameters `A` and `E_(a)`.

Text Solution

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`log_(10).(k_(2))/(k_(1))=(E_(a))/(2.3030R)((1)/(T_(1))-(1)/(T_(2)))`
`log_(10).(4.5xx10^(7))/(1.5xx10^(7))=(E_(a))/(2.303xx8.314)((1)/(323)-(1)/(373))`
`E_(a)=2.2xx10^(4)` J/mol
We know, that,
`log_(10) K =log_(10)A-(E_(a))/(2.303RT)`
`log _(10)(1.5xx10^(7))=log _(10)A-(2.2xx10^(4))/(2.303xx8.314xx323)`
`A=5.2xx10^(10)s^(-1)`
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