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in a reacton, of acidified hydrogen pero...

in a reacton, of acidified hydrogen peroxide with potassium iodide, the concentration of iodine formed rises from 0 to `10^(-5) "mil dm"^(-3)` in 10 seconds. What is the rate of reaction ?

A

`10^(-6)"mol dm"^(-3)s^(-1)`

B

`10^(6)"mol dm"^(-3)s^(-1)`

C

`10^(-5)"mol dm"^(-3)s^(-1)`

D

`10^(4)"mol dm"^(-3)s^(-1)`

Text Solution

Verified by Experts

The reaction is
`2I^(-)+H_(2)O_(2)+2H^(+)rarrI_(2)+2H_(2)O`
`"Rate"=+(d[I_(2)])/(dt)=(10^(-5))/(10)=10^(-6) "mol dm"^(-3)s^(-1)`
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