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For a gaseous reaction, following data i...

For a gaseous reaction, following data is given:
`ArarrB, k_(1)= 10^(15)e-^(2000//T)`
`C rarrD, k_(2) = 10^(14)e^(-1000//T)`
The temperature at which `k_(1) = k_(2)` is

A

1000K

B

2000 K

C

`868.82 K`

D

`443.2 K`

Text Solution

Verified by Experts

When `k_(1)=k_(2)`
`10^(15)e^(-2000//T)=10^(14)e^(-1000//T)`
`10= e^(1000//T)`
`2.303 log 10 =(1000)/(T)`
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