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The rate of the reaction 3A + 2B rarr ...

The rate of the reaction
`3A + 2B rarr` Products
is given by the rate expresison: Rate `= k[A][B]^(2)`
If `A` is taken in excess, the order of the reaction would be

A

3

B

2

C

1

D

5

Text Solution

Verified by Experts

When A is taken in excess, its, concentration will become constant , the rate law may , therefore, be given as :
Rate `=k[B]^(n)`
Order =2
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