At T (K) , if the rate constant of a first order reaction is `4.606xx10^(-3)s^(-1)`, the time to reduce the initial concentration of the reactant to `(1)/(10)` in seconds is :

Options

A. 500
B. 1000
C. 100
D. 50

Explanation

For first order reaction :
`k=(2.303)/(t)log.([R_(0)])/([R_(t)])`
`4.606xx10^(-3)=(2.303)/(t)log.((1)/(1//10))`
`t=(2.303)/(4.606xx10^(-3))=500 sec`