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The rate of a reaction doubles when its ...

The rate of a reaction doubles when its temperature changes form `300 K` to `310 K`. Activation energy of such a reaction will be:
`(R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)`

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The correct Answer is:
`53.59 kJ "mol"^(-1)`
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The rate temperature changes from 300K to 310K. Activation energy of such a reaction will be (R = 8.314 JK^(-1) mol^(-1) " and " log 2 = 0.3010)

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