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The reaction 2NO+O(2)rarr2NO(2) follows ...

The reaction `2NO+O_(2)rarr2NO_(2)` follows the rate law `=k[NO]^(2)[O_(2)]`. What is the order of the reaction? If `k=2.0xx10^(-6) "mol"^(-2) L^(2)s^(-1)`. What is the rate of the reaction when `=[NO]=0.04 "mol"L^(-1) and [O_(2)]=0.2"mol" L^(-1)` ?

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Verified by Experts

The correct Answer is:
Order of the reaction =3;
Rate =`6.4xx10^(-10)"mol" L^(-1)s^(-1)`
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