The data given below are for the reaction of `NO` and `Cl_(2)` to from `NOCl` at `295 K`.
`{:([Cl_(2)],[NO],,,"Initial rate" (mol litre^(-1) sec^(-1))),(0.05,0.05,,,1xx10^(-3)),(0.15,0.05,,,3xx10^(-3)),(0.05,0.15,,,9xx10^(-3)):}`
(a) What is the order with respect to `NO` and `Cl_(2)` in the reaction?
(b) Write the rate expression.
(c ) Calculate the rate constant.
(d) Determine the reaction rate when conc. of `Cl_(2)` and `NO` are `0.2 M` and `0.4 M` respectively.

Answer

(a) Order w.r.t. NO= 2; order w.r.t. `Cl_(2)` =1
(b) Rate expression `r=k[NO]^(2)[Cl_(2)]`
(c) `k=8.0 L^(2)"mol"^(2)s^(-1)`
(d) Rate `=0.256 "mol" L^(-1)s^(-1)`