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For the reaction, 2NH(3)rarr N(2)+3H(2) ...

For the reaction, `2NH_(3)rarr N_(2)+3H_(2)`
if `(-d[NH_(3)])/(dt)=k_(1)[NH_(3)]`,
`(d[N_(2)])/(dt)=k_(2)[NH_(3)], (d[H_(2)])/(dt)=k_(3)[NH_(3)]`
then the relation between `k_(1), k_(2)` and `k_(3)` is

A

`k_(1)=k_(2)=k_(3)`

B

`3k_(1)=6k_(2)=2k_(3)`

C

`2k_(1)=3k_(2)=6k_(3)`

D

`6k_(1)=3k_(2)=2k_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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