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At 100 K, a reaction is 30% complete in ...

At 100 K, a reaction is `30%` complete in 10 minutes, while at 200 K, 30% is complete in 5 minutes . The activation energy of the reaction is :

A

`2050 J`

B

4000 J

C

3000 J

D

1150 J

Text Solution

Verified by Experts

The correct Answer is:
D
We know:
`log_(10)((k_(2))/(k_(1)))=(E_(a))/(2.303R)xx((1)/(T_(1))-(1)/(T_(2)))`
`log_(2)=(E_(a))/(2.303xx8.314)xx((1)/(100)-(1)/(200))`
`E_(a)=1150 J "mol"^(-1)`
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