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Initial concentration of reactant for nt...

Initial concentration of reactant for nth order reaction is 'a'. Which of the following relations is correct about `t_(1//2)` of the reaction?

A

`lnt_(1//2)`= ln (constant)-(n-1) `log_(e)a`

B

`lnt_(1//2)`=ln n+ln (constant)-ln a

C

`t_(1//2)` ln n =ln (constant) + ln `a_(0)`

D

`lnt_(1//2)`= n ln `a_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A

`t_(1//2)prop(1)/(a^(n-1))`
`t_(1//2)=k(1)/(a^(n-1))`
ln `t_(1//2)`=ln-k(n-1) `log_(e)a`
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