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The rate constant for the reaction: 2N...

The rate constant for the reaction:
`2N_(2)O_(5) rarr 4NO_(2)+O_(2)` is `3.0xx10^(-5) sec^(-1)`. If the rate is `2.40xx10^(-5) M sec^(-1)`, then the concentration of `N_(2)O_(5)` (in M) is:`

A

`1.4`

B

`2.1`

C

`1.27`

D

`0.8`

Text Solution

Verified by Experts

The correct Answer is:
D
Rate = `k[N_(2)O_(5)]`
`2.4xx10^(-5)=3xx10^(-5)[N_(2)O_(5)]`
`[N_(2)O_(5)]=0.8M`
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