In the hober's process of ammonia manufacture,
`N_(2)(g)+3H_(2)(g) rarr2NH_(3)(g)`
the rate of appearance of `NH_(3)` is :
`(d[NH_(3)])/(dt)=2xx10^(-4)"mol" L^(-1)"sec"^(-1)`
The rates of the reaction expressed in terms of `N_(2) and H_(2)` will be :

Answer

B

Explanation

Rate `=+(1)/(2)(d[NH_(3)])/(dt)=(-d[N_(2)])/(dt)=-(1)/(3)(d[H_(2)])/(dt)`
`(-d[H_(2)])/(dt)=(3)/(2)xx(d[NH_(3)])/(dt)`
`=(3)/(2)xx2xx10^(-4)"mol" L^(-1)sec^(-1)`
`(-d[N_(2)])/(dt)=(1)/(2)xx(d[NH_(3)])/(dt)=(1)/(2)xx2xx10^(-4)`
`=1xx10^(-4) "mol" L^(-1)sec^(-1)`