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In the reaction, 3BrO^(-)rarrBrO(3)^(...

In the reaction,
`3BrO^(-)rarrBrO_(3)^(-)+2Br^(-)` (aqueous alkaline medium at `80^(@)C`) the vlaue of the rate constant in the rate law in terms of `--(d)/(dt)[BrO^(-)]` is `0.056 L "mol"^(-1)s^(-1)`. What will be the rate constant when the law is stated in terms of `(d)/(dt)[BrO^(-)]`?

A

`18.7xx10^(-3) L"mol"^(-1)s^(-1)`

B

`37.4xx10^(-3) L"mol"^(-1)s^(-1)`

C

`0.0187 L"mol"^(-1)s^(-1)`

D

`0.0187xx10^(-2) L"mol"^(-1)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`-(1)/(3)(d[BrO^(-)])/(dt)=(d[BrO_(3)^(-)])/(dt)=+(1)/(3)(d[Br^(-)])/(dt)`
Required rate constant `=(1)/(3)xx0.056 L "mol"^(-1)s^(-1)`
`=0.0187 L "mol"^(-1)s^(-1)`
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