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The rate law for a reaction between A an...

The rate law for a reaction between `A` and `B` is given by rate `= k[A]^(n)[B]^(m)`. On doubling the concentration of `A` and halving the concentration of `B`, the ratio of the new rate to the earlier rate of the reaction becomes

A

`(1)/(2^(m+n))`

B

m+n

C

m-n

D

`2^(n-m)`

Text Solution

Verified by Experts

The correct Answer is:
D
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