Which hydrocarbon is consistent with the following formation ? Molecular mass =72 gives a single monochloride and two dichlorides on photochlorination.

Explanation

Let the hydrocarbon be `C_(n)H_(2n+3,)` i.e., `12n +2n +2 =72 " or " n =5.`The hydrocarbon is `C_(5)H_(12).` As it forms a single monochloride, all the hydrogen atoms are equivalent . The compound is `(CH_(3))_(4)C` i.e., neopentane. Single chloro derivative is `(CH_(3))_(3)C CH_(2)CI` and the two dichlorides are `(CH_(3))_(3) C CHCI_(2) " and " (CH_(3))_(2)C(CH_(2)CI)_(2)`