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Which of the following alkyl halides is ...

Which of the following alkyl halides is hydrolysis by `S_(N^(2))` mechanism?

A

`H_(2)C=CHCH_(2)Br`

B

`(CH_(3))_(3) CBr`

C

`CH_(3)Br`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine which alkyl halide undergoes hydrolysis by the \( S_N2 \) mechanism, we need to analyze the stability of the carbocations formed during the reaction. The \( S_N2 \) mechanism involves a nucleophilic substitution that is bimolecular, meaning it depends on both the substrate (alkyl halide) and the nucleophile. ### Step-by-Step Solution: 1. **Understand the \( S_N2 \) Mechanism**: - The \( S_N2 \) mechanism involves a nucleophile attacking the carbon atom bonded to the halide from the opposite side, leading to a transition state where both the nucleophile and the leaving group (halide) are partially bonded to the carbon. This results in the inversion of configuration at the carbon center. 2. **Identify the Alkyl Halides**: - We have three alkyl halides to consider: 1. \( CH_2=CH-CH_2Br \) (Allyl bromide) 2. \( (CH_3)_3CBr \) (Tert-butyl bromide) 3. \( CH_3Br \) (Methyl bromide) 3. **Analyze Each Alkyl Halide**: - **Option 1: \( CH_2=CH-CH_2Br \)** (Allyl bromide) - Removing the bromine forms an allyl carbocation, which can be stabilized by resonance. However, this stabilization makes it less favorable for \( S_N2 \) because \( S_N2 \) prefers less stable carbocations. - **Option 2: \( (CH_3)_3CBr \)** (Tert-butyl bromide) - Removing the bromine forms a tertiary carbocation, which is highly stable. However, tertiary carbocations do not favor \( S_N2 \) reactions due to steric hindrance. Thus, this option is also not favorable for \( S_N2 \). - **Option 3: \( CH_3Br \)** (Methyl bromide) - Removing the bromine forms a methyl carbocation, which is the least stable but is not hindered sterically. This makes it highly favorable for \( S_N2 \) reactions. 4. **Conclusion**: - Based on the analysis, the only alkyl halide that undergoes hydrolysis by the \( S_N2 \) mechanism is **Option 3: \( CH_3Br \)** (Methyl bromide). ### Final Answer: The alkyl halide that is hydrolyzed by the \( S_N2 \) mechanism is **\( CH_3Br \)**.
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OP TANDON-HALOALKANES AND HALOARENES -Objective Questions
  1. (CH(3))(2)CHCI +Nal to (CH(3))(2) CHI +NaCI The above reaction is kn...

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  2. Which of the following haloalkanes would undergo S(N^(2)) reaction fas...

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  3. Which of the following alkyl halides is hydrolysis by S(N^(2)) mechani...

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  4. Ethene on treatment with bromine in presence of NaCI solution gives:

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  5. the non-reactivity of chlorine atom in H(2) C=CH-CI is due to :

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  6. Ethyl orthoformate is formed by heating "…….." with sodium ethoxide.

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  7. What happens when C CI(4) is treated with AgNO(3) solution ?

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  8. If 1,3- dibromopropane reacts with zinc and NaI, the product obtained ...

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  9. Which one of the following does not give white precipitate with acidif...

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  10. The hydrolysis of optically active 2-bromobutane with aqueous NaOH res...

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  11. Chloroform on reduction with zinc and water gives:

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  12. When carbon tetrachloride is reduced with Zn and H(2)SO(4) alcoholic s...

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  13. Pure chloroform may be prepared by :

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  14. When pure chloroform is shaken with silver nitrate solution we get :

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  15. When pure chloroform is shaken with silver nitrate solution we get :

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  16. When alkyl halide is heated with an aqueous ethanolic solution of silv...

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  17. When ethyl chloride is heated with AgCN, the main product is :

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  18. When a solution of sodium chloride containing ethyl alcohol is electro...

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  19. Ethyl alcohol on treatment with bleaching powder gives chloroform .Whi...

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  20. Which one of the following is not expected to undergo iodoform reacti...

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