Which one of the following compounds is stable?

Options

A. `CH_(3)CH(OH)_(2)`
B. `(CH_(3))_(2)C(OH)_(2)`
C. `C Cl_(3)CH(OH)_(2)`
D. None of thse

Answer

To determine which compound is stable among the given options, we need to analyze the structures and the presence of functional groups in each compound.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We have three compounds to analyze:
- **Compound 1**: \( \text{CS}_3\text{CH(OH)}_2 \)
- **Compound 2**: \( \text{CS}_3\text{C(CS}_3)(\text{OH})_2 \)
- **Compound 3**: \( \text{Cl}_3\text{C(OH)}_2 \)

2. **Recognize the Functional Groups**:
All three compounds are geminal diols, meaning they have two hydroxyl (–OH) groups attached to the same carbon atom.

3. **Consider Dehydration Reactions**:
Each compound can undergo dehydration to form a more stable compound. The dehydration reaction involves the removal of water (H2O) and the formation of a carbonyl compound.

4. **Analyze Electron Donating and Withdrawing Effects**:
- **Compound 1** has two methyl groups (–CS3), which are electron-donating groups. This can reduce the stability of the geminal diol because they decrease the partial positive charge on the carbon, making it less electrophilic and less reactive.
- **Compound 2** also has two methyl groups, which similarly reduce the stability for the same reasons as Compound 1.
- **Compound 3** has three chlorine atoms (–Cl), which are electron-withdrawing groups. This increases the partial positive charge on the carbon, enhancing its electrophilicity and making the compound more stable during the dehydration reaction.

5. **Conclusion**:
Since the electron-withdrawing groups in Compound 3 stabilize the geminal diol and facilitate the dehydration reaction, we conclude that **Compound 3** is the most stable among the three options. Therefore, the answer is **Option C**.