Number of isomers represented by molecular formula `C_(4)H_(10)O` is `:`

Options

A. 3
B. 4
C. 7
D. 10

Answer

To determine the number of isomers represented by the molecular formula C₄H₁₀O, we will analyze the possible structural isomers that can be formed with this formula, focusing on ethers, alcohols, aldehydes, and ketones.

### Step-by-Step Solution:

1. **Identify the Functional Groups**:
The molecular formula C₄H₁₀O can represent different types of compounds: ethers, alcohols, aldehydes, and ketones.

2. **Count Isomers for Ethers**:
- The first ether is CH₃-CH₂-O-CH₂-CH₃ (diethyl ether).
- The second ether is CH₃-O-CH₂-CH₃ (ethyl methyl ether).
- The third ether is CH₃-CH₂-O-CH₃ (methoxypropane).

Total ethers: **3**

3. **Count Isomers for Alcohols**:
- The first alcohol is CH₃-CH₂-CH₂-CH₂-OH (butanol).
- The second alcohol is CH₃-CH(CH₃)-CH₂-OH (2-butanol).
- The third alcohol is CH₃-CH₂-CH(OH)-CH₃ (isobutanol).
- The fourth alcohol is CH₃-CH(OH)-CH₃ (tert-butanol).

Total alcohols: **4**

4. **Count Isomers for Aldehydes**:
- The only possible aldehyde is CH₃-CH₂-CH₂-CHO (butanal).

Total aldehydes: **1**

5. **Count Isomers for Ketones**:
- The only possible ketone is CH₃-CO-CH₂-CH₃ (butanone).

Total ketones: **1**

6. **Total Isomers**:
Now, we add the total number of isomers from each category:
- Ethers: 3
- Alcohols: 4
- Aldehydes: 1
- Ketones: 1

Total isomers = 3 (ethers) + 4 (alcohols) + 1 (aldehyde) + 1 (ketone) = **9**

### Final Answer:
The total number of isomers represented by the molecular formula C₄H₁₀O is **9**.

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