Carbon-oxygen double bond are easily reduced by `NaBH_(4)` or `LiAlH_(4)`. The actual reducing agent in these reduction is hydride ion `(H^(-))`.
The metal-hydrogen bond in `LiAlH_(4)` is more polar than metal-hydrogen bond in `NaBH_(4)`. As a result `LiAlH_(4)` is strong reducing agent than `NaBH_(4)`. Esters, carboxylic acids, amides cannot be reducted by `NaBH_(4)`.
The carbonyl group of amide to methylene group by `LiAlH_(4)`.
Find the correct product of the following reaction `:`

Options

A.
B.
C.
D. No reaction

Answer

C