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Carbon-oxygen double bond are easily red...

Carbon-oxygen double bond are easily reduced by `NaBH_(4)` or `LiAlH_(4)`. The actual reducing agent in these reduction is hydride ion `(H^(-))`.
The metal-hydrogen bond in `LiAlH_(4)` is more polar than metal-hydrogen bond in `NaBH_(4)`. As a result `LiAlH_(4)` is strong reducing agent than `NaBH_(4)`. Esters, carboxylic acids, amides cannot be reducted by `NaBH_(4)`.
The carbonyl group of amide to methylene group by `LiAlH_(4)`.
`underset(D_(2)O)overset(LiAlH_(4))(rarr)'Y' , ` Identify 'Y'`:`

A

`CH_(3)-overset(OH)overset(|)(C)-CH_(2)-overset(OH)overset(|)(C)H-CH_(3)`

B

`CH_(3)-underset(D)underset(|)overset(OH)overset(|)(C)-CH_(2)-CH_(2)-OD`

C

`CH_(3)-overset(OD)overset(|)(C)H-CH_(2)-overset(OH)overset(|)(C)H-CH_(3)`

D

`CH_(3)-overset(OD)overset(|)(C)H-CH_(3)-overset(OD)overset(|)(C)H-CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
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