Radius of the circle `x^2 +y^2 + 2xcos theta + 2y sin theta-8=0`, is

Radius of the circle x^(2)+y^(2)+2x cos theta+2y sin theta-8=0, is

Radius of the circle x^(2)+y^(2)+2x cos theta+2y sin theta-8=0 is 12 . 33.2sqrt(3)4.sqrt(10)5.2

Radius of the circle x^2+y^2+2x costheta+2y sin theta-8=0 is 1 2. 3 3. 2sqrt(3) 4. sqrt(10) 5. 2

Find the centre and radius of the circles : 1/2 (x^2 + y^2) + x cos theta + y sin theta - 4 = 0

Find the centre and radius of the circles : 1/2 (x^2 + y^2) + x cos theta + y sin theta - 4 = 0

Find the centre and the radius of the circles x^(2) + y^(2) + 2x sin theta + 2 y cos theta - 8 = 0

Find the centre and the radius of the circles x^(2) + y^(2) + 2x sin theta + 2 y cos theta - 8 = 0

The locus of the centre of the circle : x^2+y^2+4x cos theta - 2 y sin theta - 10 = 0 is ,

The locus of the centre of the circle x^(2)+y^(2)+4x cos theta-2y sin theta-10=0 is (A) An ellipse(B) A circle(C) A hyperbola