Let `a_1,a_2,a_3……….` be term of an A.P. if `(a_1+a_2+….+a_p)/(a_1+a_2+………+a_q)=p^2/q^2 p!=q` then `a_6/ a_21` euqals `(A) 41/11 (B) 11/41 (C) 13/44 (D) 15/41`

Let a_1 , a_2 , a_3,.... be terms of an A.P. if (a_1 + a_2 +....+ a_p)/(a_1 + a_2 +...+ a_q) = p^2/q^2. p ne q then a_6/a_21 equals

If a_1, a_2, a_3, be terms of an A.P. if (a_1+a_2+...+a_p)/(a_1+a_2+...+a_q)=(p^2)/(q^2), p!=q ,t h e n(a_6)/(a_(21)) equals

If a_1, a_2, a_3, be terms of an A.P. and (a_1+a_2+.....+a_p)/(a_1+a_2+.....+a_q)=(p^2)/(q^2), p!=q ,t h e n(a_6)/(a_(21)) equals to (a).41/11 (b). 7/2 (c). 2/7 (d). 11/41

If a_1, a_2, a_3, be terms of an A.P. and (a_1+a_2+.....+a_p)/(a_1+a_2+.....+a_q)=(p^2)/(q^2), p!=q ,t h e n(a_6)/(a_(21)) equals to (a).41/11 (b). 7/2 (c). 2/7 (d). 11/41

Let a_1,a_2,a_3,...... be an A.P. such that [a_1+a_2+......+a_p]/[a_1+a_2+a_3+......+a_q]=p^3/q^3 ; p!=q .Then a_6/a_[21] is equal to:

Let a_1,a_2," ..."a_10 be a G.P. If a_3/a_1=25," then "a_9/a_5 equals

Let a_1,a_2 ,a_3 …..be in A.P. and a_p, a_q , a_r be in G.P. Then a_q : a_p is equal to :

Let a_1,a_2 ,a_3 …..be in A.P. and a_p, a_q , a_r be in G.P. Then a_q : a_p is equal to :

Let a_1, a_2 , a_3 and a_4 be in AP. If a_1 + a_4 =10 and a_2. a_3 =24 , then the least term of the AP, is