(sin18)/(cos72)

Evaluate : (i) (sin18o)/(cos72o) (ii) (tan26o)/(cot64o) (iii) cos48o-sin42o (iv) "c o s e c 31osec""""59o"

(sin18^0)/(cos72^0)+(sin22^0)/(cos68^0)-(cos38^0cos e c52^0)/(tan18^0tan35^0tan60^0tan72^0tan55^0)

Evaluate : (sin 18^@)/(cos 72^@)

Evaluate (Sin 18)/(Cos 72)

(sin 18^@)/( cos 72 ^@) = ?

(sin18^(0))/(cos72^(0))+(sin22^(0))/(cos68^(@))-(cos38^(0)cos ec52^(0))/(tan18^(@)tan35^(@)tan60^(@)tan72^(@)tan55^(@))

Evaluate : (sin 18^(@))/(cos72^(@))

sin 18^@-cos 72^@ is equal to : sin 18^@-cos 72^@ का मान क्या होगा ?

Evaluate : (sin 18^(@))/(cos 72^(@))

Evaluate: (i) (sin 18^(@))/(cos 72^(@))