Which of the following amino acid doesn't show degeneracy ?

Options

A. Leucine
B. Proline
C. Cysteine
D. Tryptophan

Answer

To determine which amino acid does not show degeneracy, we need to analyze the codons associated with each amino acid. Degeneracy in the genetic code refers to the phenomenon where a single amino acid can be encoded by more than one codon.

### Step-by-Step Solution:

1. **Understand the concept of degeneracy**:
- Degeneracy in the genetic code means that multiple codons can code for the same amino acid.

2. **List the amino acids provided**:
- The amino acids in question are Leucine, Proline, Cysteine, and Tryptophan.

3. **Identify the codons for each amino acid**:
- **Leucine**: Codons are CUU, CUC, CUA, CUG, UUA, UUG. (6 codons)
- **Proline**: Codons are CCU, CCC, CCA, CCG. (4 codons)
- **Cysteine**: Codons are UGC, UGU. (2 codons)
- **Tryptophan**: Codon is UGG. (1 codon)

4. **Analyze the codons for degeneracy**:
- Leucine has multiple codons (6), so it shows degeneracy.
- Proline also has multiple codons (4), so it shows degeneracy.
- Cysteine has 2 codons, so it shows degeneracy.
- Tryptophan has only 1 codon (UGG), so it does not show degeneracy.

5. **Conclusion**:
- The amino acid that does not show degeneracy is **Tryptophan**.

### Final Answer:
The amino acid that does not show degeneracy is **Tryptophan**.