Sequentially the last stage to occur among the following is :

Options

A. Diakinesis
B. Pachytene
C. Zygotene
D. Leptotene

Answer

To solve the question regarding the sequential stages of meiosis, we will analyze the stages provided: Diakinesis, Pachytene, Zygotene, and Leptotene. We will identify the order of these stages within the context of meiosis, particularly focusing on Prophase I, which consists of five distinct phases.

### Step-by-Step Solution:

1. **Understanding Meiosis**:
- Meiosis is a type of cell division that reduces the chromosome number by half and produces four genetically diverse gametes. It consists of two main stages: Meiosis I and Meiosis II.

2. **Identifying Prophase I Stages**:
- Prophase I of meiosis is divided into five stages:
1. **Leptotene**: Chromosomes become visible and start to condense.
2. **Zygotene**: Homologous chromosomes begin to pair (synapsis).
3. **Pachytene**: Tetrads form, and crossing over occurs.
4. **Diplotene**: Homologous chromosomes begin to separate, but remain attached at chiasmata.
5. **Diakinesis**: Chromosomes condense further, and the nuclear envelope breaks down, preparing for metaphase.

3. **Determining the Last Stage**:
- Among the stages listed (Diakinesis, Pachytene, Zygotene, and Leptotene), we need to identify which one occurs last in the sequence of Prophase I.
- The correct order of the stages is:
- Leptotene → Zygotene → Pachytene → Diplotene → Diakinesis.
- Therefore, the last stage of Prophase I is **Diakinesis**.

4. **Conclusion**:
- The last stage to occur among the options provided is **Diakinesis**.

### Final Answer:
**Diakinesis**