Find the odd one out with respect to the part of the plant used for food storage under unfavourable conditions.

Options

A. Potato
B. Colocasia
C. Ginger
D. Turnip

Answer

To solve the problem of identifying the odd one out with respect to the part of the plant used for food storage under unfavorable conditions, we will analyze each option provided.

### Step-by-Step Solution:

1. **Identify the Options**: The options provided are potato, ginger, colocasia, and turnip.

2. **Analyze Each Option**:
- **Potato**:
- Part of the plant: Modified stem (tuber).
- Function: Stores food in both favorable and unfavorable conditions.
- **Ginger**:
- Part of the plant: Modified stem (rhizome).
- Function: Stores food in both favorable and unfavorable conditions.
- **Colocasia**:
- Part of the plant: Modified stem (corm).
- Function: Stores food in both favorable and unfavorable conditions.
- **Turnip**:
- Part of the plant: Modified root (taproot).
- Function: Stores food primarily for use during unfavorable conditions.

3. **Compare the Storage Functions**:
- The first three options (potato, ginger, and colocasia) are all modified stems that can store food in both favorable and unfavorable conditions.
- The turnip, however, is a modified root that primarily stores food to survive unfavorable conditions.

4. **Identify the Odd One Out**:
- Since potato, ginger, and colocasia are all modified stems that serve a similar function, while turnip is a modified root that specifically stores food for unfavorable conditions, the odd one out is **turnip**.

### Conclusion:
The odd one out with respect to the part of the plant used for food storage under unfavorable conditions is **turnip**.

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