Saccharin is imide of

Options

A.
B.
C.
D.

Answer

To determine the imide of saccharin, we need to analyze its structure and identify the corresponding compound from which saccharin can be derived.

### Step-by-Step Solution:

1. **Understanding Saccharin Structure**:
- Saccharin is a compound that contains a benzene ring, a carbonyl group (C=O), and a sulfonamide group (–SO2NH).
- The structure can be represented as:
```
O
||
C
|
NH
|
S=O
||
O
```

2. **Identifying the Functional Groups**:
- The key functional groups in saccharin are the sulfonamide (–SO2NH) and the carbonyl (C=O) groups.
- For saccharin to be formed, these groups must be in specific positions on the benzene ring.

3. **Finding the Correct Precursor**:
- We need a compound that has the sulfonic acid group (–SO3H) and a carbonyl group (–COOH) positioned ortho (1,2) to each other on the benzene ring.
- This means that the compound must have the functional groups at positions 1 and 2 on the benzene ring.

4. **Evaluating the Options**:
- We analyze the given options to find which one has the sulfonic acid and carbonyl groups in the required positions.
- The correct compound should be benzene sulfonic acid with a carbonyl group in the ortho position.

5. **Conclusion**:
- The compound that can be used to make saccharin is **benzenesulfonic acid** (C6H5SO3H) with a carbonyl group (C=O) at the ortho position.
- Therefore, the answer is that saccharin is the imide of **benzenesulfonic acid**.

### Final Answer:
Saccharin is the imide of **benzenesulfonic acid**.

---