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Which of the following sets of quantum n...

Which of the following sets of quantum numbers represents an impossible arrangement?

A

`{:(n,l,m,s),(4,3,-3,1//2):}`

B

`{:(n,l,m,s),(4,1,-1,1//2):}`

C

`{:(n,l,m,s),(3,1,-2,1//2):}`

D

`{:(n,l,m,s),(4,3,0,1//2):}`

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The correct Answer is:
To determine which set of quantum numbers represents an impossible arrangement, we need to understand the rules governing the quantum numbers: 1. **Principal Quantum Number (n)**: This number can take positive integer values (1, 2, 3, ...). It indicates the energy level of the electron. 2. **Azimuthal Quantum Number (l)**: This number can take values from 0 to (n-1). It represents the subshell (s, p, d, f). 3. **Magnetic Quantum Number (m)**: This number can take values from -l to +l, including zero. It indicates the orientation of the orbital. 4. **Spin Quantum Number (s)**: This number can either be +1/2 or -1/2, representing the two possible spin states of an electron. Now, let's analyze the options given in the question step by step: ### Step 1: Analyze the first option Assuming the first option is (n=4, l=3, m=2, s=+1/2): - n = 4 (valid) - l = 3 (valid since l can be 0 to n-1, which is 0 to 3) - m = 2 (valid since m can be -3, -2, -1, 0, +1, +2, +3 for l=3) - s = +1/2 (valid) This set is possible. ### Step 2: Analyze the second option Assuming the second option is (n=3, l=2, m=1, s=-1/2): - n = 3 (valid) - l = 2 (valid since l can be 0 to n-1, which is 0 to 2) - m = 1 (valid since m can be -2, -1, 0, +1, +2 for l=2) - s = -1/2 (valid) This set is possible. ### Step 3: Analyze the third option Assuming the third option is (n=4, l=1, m=2, s=+1/2): - n = 4 (valid) - l = 1 (valid since l can be 0 to n-1, which is 0 to 3) - m = 2 (invalid since m can only take values from -1 to +1 for l=1) - s = +1/2 (valid) This set is **impossible** due to the invalid value of m. ### Step 4: Analyze the fourth option Assuming the fourth option is (n=2, l=0, m=0, s=-1/2): - n = 2 (valid) - l = 0 (valid since l can be 0 to n-1, which is 0 to 1) - m = 0 (valid since m can only be 0 for l=0) - s = -1/2 (valid) This set is possible. ### Conclusion The impossible arrangement of quantum numbers is the third option (n=4, l=1, m=2, s=+1/2).
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