In the reaction,
`CH_3 - CH_2-CBr_3overset("Ag Powder"//Delta)(rarr)(X)`. The product x is :

Options

A. Propyne
B. `CH_3 - C -= C - Ag`
C. 3 - Hexyne
D. 3 - Hexena

Answer

To solve the problem, we need to analyze the reaction of `CH3-CH2-CBr3` in the presence of silver powder (Ag) and heat (Δ). The reaction involves the elimination of bromine atoms and the formation of a carbon-carbon triple bond.

### Step-by-Step Solution:

1. **Identify the Reactant:**
The reactant is `CH3-CH2-CBr3`, which is a bromoalkane with three bromine atoms attached to the same carbon atom.

2. **Understand the Role of Silver Powder:**
Silver (Ag) acts as a reducing agent. It can react with the bromine atoms, leading to the formation of radicals. Each bromine atom will be replaced by a hydrogen atom, and AgBr will be formed as a byproduct.

3. **Elimination of Bromine Atoms:**
When `CH3-CH2-CBr3` is heated with Ag, the bromine atoms will be eliminated one by one. This process will generate a series of radicals. The first bromine will be removed, forming a radical intermediate.

4. **Formation of Carbon-Carbon Bonds:**
As bromine is eliminated, the carbon atoms will form new bonds. The radical formed on the carbon will react with another radical, leading to the formation of a double bond, and eventually a triple bond as more bromine atoms are removed.

5. **Final Product Formation:**
After the elimination of all three bromine atoms, the structure will stabilize into a carbon chain with a triple bond. The final product will be `CH3-CH2-C≡C-CH2-CH3`, which is 3-hexyne.

6. **Identify the Product:**
The product `X` formed from the reaction is 3-hexyne, which can be represented as `C6H10` with the triple bond located at the third carbon.

### Final Answer:
The product `X` is 3-hexyne.

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