The main products formed by the reaction of `N_(2)O_(5) and H_(2)O_(2)` are

Options

A. only `HNO_(3)`
B. `HNO_(3) + O_(3)`
C. `HNO_(3) +HNO_(4)`
D. `HNO_(3) + HNO_(2)`

Answer

To determine the main products formed by the reaction of \( N_2O_5 \) and \( H_2O_2 \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are dinitrogen pentoxide (\( N_2O_5 \)) and hydrogen peroxide (\( H_2O_2 \)).

2. **Write the Reaction**: The reaction can be expressed as:
\[ N_2O_5 + H_2O_2 \rightarrow ? \]

3. **Determine the Products**: When \( N_2O_5 \) reacts with \( H_2O_2 \), it typically forms nitric acid (\( HNO_3 \)) and peroxy nitric acid (\( HNO_4 \)). The balanced equation for this reaction is:
\[ N_2O_5 + H_2O_2 \rightarrow 2 HNO_3 + HNO_4 \]

4. **Check for Balancing**:
- **Nitrogen (N)**: On the left side, we have 2 nitrogen atoms from \( N_2O_5 \) and on the right side, we have 2 nitrogen atoms (2 from \( 2 HNO_3 \) and 1 from \( HNO_4 \)).
- **Oxygen (O)**: On the left side, we have 7 oxygen atoms (5 from \( N_2O_5 \) and 2 from \( H_2O_2 \)). On the right side, we also have 7 oxygen atoms (6 from \( 2 HNO_3 \) and 1 from \( HNO_4 \)).
- **Hydrogen (H)**: On the left side, we have 2 hydrogen atoms from \( H_2O_2 \) and on the right side, we also have 2 hydrogen atoms (2 from \( 2 HNO_3 \) and none from \( HNO_4 \)).

5. **Conclusion**: The balanced reaction confirms that the main products formed are:
\[ HNO_3 \text{ (Nitric Acid) and } HNO_4 \text{ (Peroxy Nitric Acid)} \]

### Final Answer:
The main products formed by the reaction of \( N_2O_5 \) and \( H_2O_2 \) are \( HNO_3 \) and \( HNO_4 \).