When alkyl halides reaction with aromatic compounds in presence of anhydrous `AlCl_3` , the reaction is known as

Options

A. Friedal - Craff reaction
B. Hofmann degradation
C. Kolbe's synthesis
D. Beckmann rearrangement

Answer

To solve the question regarding the reaction of alkyl halides with aromatic compounds in the presence of anhydrous AlCl₃, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction Type**:
- When alkyl halides react with aromatic compounds, it is a type of electrophilic aromatic substitution reaction. The presence of anhydrous AlCl₃ is crucial as it acts as a Lewis acid catalyst.

2. **Role of Anhydrous AlCl₃**:
- Anhydrous AlCl₃ facilitates the generation of a more reactive electrophile from the alkyl halide. It does this by forming a complex with the alkyl halide, which leads to the formation of a carbocation (alkyl cation).

3. **Formation of Electrophile**:
- The alkyl halide (e.g., R-X where R is an alkyl group and X is a halogen) reacts with AlCl₃ to form R⁺ (the alkyl cation) and AlCl₄⁻. The alkyl cation is the electrophile that will attack the aromatic ring.

4. **Electrophilic Attack on Aromatic Ring**:
- The generated alkyl cation (R⁺) then attacks the π electrons of the aromatic ring (e.g., benzene), leading to the formation of an alkyl-substituted aromatic compound (alkyl benzene).

5. **Final Product**:
- The final product of this reaction is an alkyl-substituted aromatic compound (e.g., toluene if the alkyl group is methyl) and AlCl₄⁻ as a byproduct.

6. **Name of the Reaction**:
- This entire process is known as the **Friedel-Crafts Alkylation** reaction. It is a well-known reaction in organic chemistry used to introduce alkyl groups into aromatic compounds.

### Conclusion:
The reaction of alkyl halides with aromatic compounds in the presence of anhydrous AlCl₃ is called **Friedel-Crafts Alkylation**.

---