A child has a die whose six faces show the letters as given below:A,B,C,D,E,A.The die is thrown once. What is the probability of getting (i) A?   (ii) D?

Explanation

Let us take
Total number of faces on the die =6

Number of faces having A on it =2

Number of faces having D on it =1

So,P(getting A)=No. of faces having A/Total number of faces​=`1/3​`

P(getting D)=No. of faces having D/Total number of faces ​=`1/6`