In the given reaction sequences the final product 'C' is
`CH_3-CH_2-OH underset((ii)H_2O^(+))overset((i)KMnO_4//overset(-)(OH)//Delta)(rarr)(A)underset((ii)NH_3)overset((i)SOCl_2)(rarr)(B) overset(Br_(2)//KOH)(rarr)(C )`

Options

A. Methylamine
B. Ethylamine
C. Propylamine
D. Acetamide

Answer

To solve the given reaction sequence and determine the final product 'C', we will break down each step of the reaction as follows:

### Step 1: Oxidation of Ethanol
The initial compound is ethanol (CH₃-CH₂-OH). When ethanol is treated with hot, alkaline potassium permanganate (KMnO₄ in the presence of OH⁻), it undergoes oxidation.

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{KMnO}_4, \Delta} \text{CH}_3\text{COOH} \]

**Product A:**
The product formed after oxidation is acetic acid (CH₃COOH).

### Step 2: Conversion of Acetic Acid to Acetyl Chloride
Next, acetic acid (CH₃COOH) is reacted with thionyl chloride (SOCl₂) and ammonia (NH₃).

**Reaction:**
1. Acetic acid reacts with SOCl₂ to form acetyl chloride (CH₃COCl) and releases SO₂ and HCl as by-products.
2. The acetyl chloride then reacts with ammonia (NH₃) to form acetamide (CH₃CONH₂).

**Product B:**
The product after this step is acetamide (CH₃CONH₂).

### Step 3: Degradation of Acetamide
Finally, acetamide (CH₃CONH₂) is treated with bromine (Br₂) in the presence of potassium hydroxide (KOH). This reaction is known as the Hofmann degradation.

**Reaction:**
\[ \text{CH}_3\text{CONH}_2 \xrightarrow{\text{Br}_2/\text{KOH}} \text{CH}_3\text{NH}_2 + \text{by-products} \]

**Product C:**
The major product formed from this reaction is methylamine (CH₃NH₂).

### Final Answer:
Thus, the final product 'C' is methylamine (CH₃NH₂).

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