Home
Class 12
CHEMISTRY
The specific rotation of a pure enantiom...

The specific rotation of a pure enantiomer is `+16^@`. The observed rotation, if it is isolated from a reaction with 25% racemisation and 75% inversion is

A

`+12^@`

B

`-12^@`

C

`4^@`

D

`-4^@`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the observed rotation of a pure enantiomer that has undergone a reaction resulting in 25% racemization and 75% inversion. The specific rotation of the pure enantiomer is given as +16°. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Specific rotation of the pure enantiomer (\[ \alpha_{pure} \]) = +16° - Percentage of racemization = 25% - Percentage of inversion (or retention) = 75% 2. **Calculate the Contribution from Inversion:** - The observed rotation due to the retained enantiomer (inversion) can be calculated using the formula: \[ \text{Observed Rotation} = \text{Specific Rotation} \times \text{Percentage Retention} \] - Here, the percentage retention is 75%, which means: \[ \text{Observed Rotation from Inversion} = +16° \times \frac{75}{100} = +12° \] 3. **Calculate the Contribution from Racemization:** - The racemization results in the formation of the opposite enantiomer. Since 25% of the original enantiomer is converted to the opposite enantiomer, the contribution from this racemization will be: \[ \text{Observed Rotation from Racemization} = -\text{Specific Rotation} \times \text{Percentage Racemization} \] - Thus: \[ \text{Observed Rotation from Racemization} = -16° \times \frac{25}{100} = -4° \] 4. **Combine the Contributions:** - Now, we can find the total observed rotation by adding the contributions from inversion and racemization: \[ \text{Total Observed Rotation} = \text{Observed Rotation from Inversion} + \text{Observed Rotation from Racemization} \] - Therefore: \[ \text{Total Observed Rotation} = +12° + (-4°) = +8° \] ### Final Answer: The observed rotation, if it is isolated from a reaction with 25% racemization and 75% inversion, is **+8°**.
Promotional Banner

Topper's Solved these Questions

  • NTA NEET TEST 111

    NTA MOCK TESTS|Exercise CHEMISTRY|45 Videos
  • NTA NEET TEST 22

    NTA MOCK TESTS|Exercise CHEMISTRY|45 Videos

Similar Questions

Explore conceptually related problems

The specific rotation of a pure enantiomer is +10^(@) . The observed rotation, if it is isolated from a reaction with 30% recemisation and 70% inversion is

The specific rotation of a pure enantiomer is +16^(@) its observed rotation if it is isolated from a reaction with 25% racemisation and 75% retention is,

a. The specific rotation of a pure enantiomer is +10^(@) . What will be its observed rotation if its is isolated from a reaction with i. 30% racemisation and 70% retention. ii. 70% racemisation and 30% inversion. b. What is the percentage composition of a mixtrue of two enantiomers whose rotation is -10^(@) ? The specific rotation of pure enantiomers is -20^(@) . c. What is the optical purity of a sample having an [alpha]_(obs.)=+9.0^(@) if [alpha]_(D)=+12^(@) .

The specific rotation of a pure enantiomers is +12^(@) . What will be its observed rotation if it is isolated form a reaction with 20% racemization and 80% retention.

The specific rotation of a pure enantiomers is +12^(@) . What will be its observed rotation if it is isolated form a reaction with 80% racemization and 20% inversion.

(+) mandelic acid has a specific rotation of 158^(@) What would be the observed specific rotation of a mixture of 25% (-) mandelic acid and 75% (+) mandelic acid ?

Two I-order reaction have half-lives in the ratio 3:2 .Calculate the ratio of time intervals t_(1),t_(2) . Where t_(1) is the time period for 25% completion of the first reaction and t_(2) , for 75% completion of the second reaction.

NTA MOCK TESTS-NTA NEET TEST 112-CHEMISTRY
  1. In the given reaction, CH(3)-underset(CH3)underset(|)(CH)-overset(O)...

    Text Solution

    |

  2. A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the ...

    Text Solution

    |

  3. The compound H2N -Hg-O-Hg-I is formed by the action of

    Text Solution

    |

  4. The value of Lambda(eq)^(oo) for NH(4)Cl, NaOH and NaCl are 149.74, 24...

    Text Solution

    |

  5. The solubility (S) of solute in water varies with temperature as given...

    Text Solution

    |

  6. What is incorrect regarding natural rubber? 1. It is cis polyisopren...

    Text Solution

    |

  7. Arrange reactivity of given compounds in decreasing order with benzald...

    Text Solution

    |

  8. The movement of sol particles under an applied electric field is calle...

    Text Solution

    |

  9. The following data were obtained at a certain temperature for the deco...

    Text Solution

    |

  10. In the given reaction sequences the final product 'C' is CH3-CH2-OH ...

    Text Solution

    |

  11. In the given sequence HOCH2-CHOH-CH2OH overset(Br2//H2O)(rarr)A + B ...

    Text Solution

    |

  12. The donor atoms in EDTA are-

    Text Solution

    |

  13. The concentration of iron, lead ,nitrate, and fluoride in a water samp...

    Text Solution

    |

  14. Acetic acid and propionic acid have K(a) values 1.75xx10^(-5) and 1.3x...

    Text Solution

    |

  15. One of the following metals forms a volatile compound and this propert...

    Text Solution

    |

  16. Consider the statements for given reaction 1. In the first step, ...

    Text Solution

    |

  17. In a constant volume calorimeter, 3.5 g of a gas with molecular weight...

    Text Solution

    |

  18. Which of the following arrangements shows the schematic alignment of m...

    Text Solution

    |

  19. The specific rotation of a pure enantiomer is +16^@. The observed rot...

    Text Solution

    |

  20. The ionisation energy of H atom is 13.6 eV. What will be the ionisa...

    Text Solution

    |