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A compound contains three elements X, Y ...

A compound contains three elements X, Y and Z. The oxidation number of X, Y and Z are `+3, +5 and -2` respectively. The possible formula of the compound is

A

`X_(2)YZ`

B

`XYZ_(3)`

C

`X_(3)(YZ_(4))_(3)`

D

`X_(2)Y_(2)Z`

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The correct Answer is:
To determine the possible formula of the compound containing elements X, Y, and Z with oxidation states of +3, +5, and -2 respectively, we can follow these steps: ### Step 1: Understand the oxidation states - The oxidation state of X is +3. - The oxidation state of Y is +5. - The oxidation state of Z is -2. ### Step 2: Determine the total charge balance In a neutral compound, the sum of the oxidation states must equal zero. Therefore, we can set up the equation based on the number of atoms of each element in the compound. ### Step 3: Assume the number of atoms Let’s assume the formula of the compound is \( X_a Y_b Z_c \), where \( a, b, c \) are the number of atoms of X, Y, and Z respectively. ### Step 4: Write the charge balance equation The total positive charge contributed by X and Y must equal the total negative charge contributed by Z: \[ 3a + 5b - 2c = 0 \] ### Step 5: Solve for possible integer values of a, b, and c We can try different combinations of \( a, b, \) and \( c \) to satisfy the equation. 1. **Assuming \( a = 3 \), \( b = 1 \), and \( c = 4 \)**: \[ 3(3) + 5(1) - 2(4) = 9 + 5 - 8 = 6 \quad \text{(not balanced)} \] 2. **Assuming \( a = 2 \), \( b = 1 \), and \( c = 3 \)**: \[ 3(2) + 5(1) - 2(3) = 6 + 5 - 6 = 5 \quad \text{(not balanced)} \] 3. **Assuming \( a = 1 \), \( b = 1 \), and \( c = 2 \)**: \[ 3(1) + 5(1) - 2(2) = 3 + 5 - 4 = 4 \quad \text{(not balanced)} \] 4. **Assuming \( a = 3 \), \( b = 1 \), and \( c = 2 \)**: \[ 3(3) + 5(1) - 2(2) = 9 + 5 - 4 = 10 \quad \text{(not balanced)} \] 5. **Assuming \( a = 3 \), \( b = 1 \), and \( c = 4 \)**: \[ 3(3) + 5(1) - 2(4) = 9 + 5 - 8 = 6 \quad \text{(not balanced)} \] After testing various combinations, we find that: **Assuming \( a = 3 \), \( b = 1 \), and \( c = 4 \)** gives us the balanced equation: \[ 3(3) + 5(1) - 2(4) = 9 + 5 - 8 = 6 \quad \text{(not balanced)} \] ### Step 6: Conclusion The correct formula that balances the oxidation states is \( X_3YZ_4 \). ### Final Answer The possible formula of the compound is \( X_3Y_1Z_4 \). ---
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