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An organic compound (P) having molecular...

An organic compound (P) having molecular mass 180 is acylated with `CH_(3)COCl` to get a new compound with molecular mass 348. The number of amino groups present per molecule of compound (P) is

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To solve the problem, we need to determine the number of amino groups present in the organic compound (P) based on the given molecular masses before and after acylation. ### Step-by-Step Solution: 1. **Identify the Molecular Masses**: - The molecular mass of compound (P) is given as 180 g/mol. - After acylation with CH₃COCl, the new compound has a molecular mass of 348 g/mol. 2. **Calculate the Increase in Molecular Mass**: - The increase in molecular mass due to acylation can be calculated as: \[ \text{Increase in mass} = \text{Final mass} - \text{Initial mass} = 348 - 180 = 168 \text{ g/mol} \] 3. **Determine the Increase in Mass per Amino Group**: - When one amino group (NH₂) is acylated, it forms an amide (NHCOCH₃). - The molecular mass of NH₂ is: \[ \text{Molecular mass of NH₂} = 14 \text{ (N)} + 2 \text{ (H)} = 16 \text{ g/mol} \] - The molecular mass of the acylated product (NHCOCH₃) is: \[ \text{Molecular mass of NHCOCH₃} = 14 \text{ (N)} + 1 \text{ (H)} + 12 \text{ (C)} + 16 \text{ (O)} + 12 \text{ (C)} + 3 \text{ (H)} = 58 \text{ g/mol} \] - The increase in mass when one NH₂ group is acylated is: \[ \text{Increase in mass per NH₂} = 58 - 16 = 42 \text{ g/mol} \] 4. **Calculate the Number of Amino Groups**: - To find the number of amino groups (n) in compound (P), we can set up the equation based on the total increase in mass: \[ n \times \text{Increase in mass per NH₂} = \text{Total increase in mass} \] - Substituting the known values: \[ n \times 42 = 168 \] - Solving for n: \[ n = \frac{168}{42} = 4 \] 5. **Conclusion**: - The number of amino groups present per molecule of compound (P) is **4**.
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