The number of stereo isomers possible for a compound of the molecular formula is `CH_(3)-CH=CH-CH(NH_(2))-CH_(3)` is

Answer

To determine the number of stereoisomers for the compound with the molecular formula CH₃-CH=CH-CH(NH₂)-CH₃, we will follow these steps:

### Step 1: Identify the Structure
First, we need to draw the structure of the compound based on the given molecular formula. The compound can be represented as follows:

```
CH3
|
CH3-CH=CH-CH(NH2)
```

### Step 2: Identify Double Bonds and Chiral Centers
Next, we need to identify any double bonds and chiral centers in the molecule.

1. **Double Bond**: The compound has a double bond between the second and third carbon atoms (C2=C3).
2. **Chiral Center**: The fourth carbon (C4) is attached to four different groups:
- NH₂ (amino group)
- CH₃ (methyl group)
- H (hydrogen)
- CH₂ (part of the chain)

### Step 3: Determine Stereoisomers from the Double Bond
The double bond can lead to cis-trans isomerism:
- **Cis Isomer**: Both higher priority groups (CH₃ and NH₂) are on the same side of the double bond.
- **Trans Isomer**: The higher priority groups are on opposite sides.

Thus, we have two configurations from the double bond:
1. Cis
2. Trans

### Step 4: Determine Stereoisomers from the Chiral Center
The chiral center (C4) can exist in two configurations:
- **R Configuration**
- **S Configuration**

### Step 5: Calculate Total Stereoisomers
Now, we combine the results from the double bond and the chiral center:
- From the double bond: 2 configurations (cis and trans)
- From the chiral center: 2 configurations (R and S)

The total number of stereoisomers can be calculated as:
\[ \text{Total Stereoisomers} = (\text{Number from double bond}) \times (\text{Number from chiral center}) \]
\[ \text{Total Stereoisomers} = 2 \times 2 = 4 \]

### Final Answer
The total number of stereoisomers possible for the compound CH₃-CH=CH-CH(NH₂)-CH₃ is **4**.

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