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Two planets A and B have the same averge...

Two planets A and B have the same averge density . Their radii `R_A and R_B` are such that `R_A : R_B = 3 : 1`. If `g_A` and `g_B` are the acceleration due to gravity at the surfaces of the planets, the `g_A : g_B` equals

A

`3 : 1`

B

`1 : 3`

C

`1 : 9`

D

`sqrt(3) : 1`

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The correct Answer is:
To solve the problem, we need to determine the ratio of the acceleration due to gravity at the surfaces of two planets, A and B, given that they have the same average density and their radii are in the ratio of 3:1. ### Step-by-Step Solution: 1. **Understanding the Formula for Acceleration due to Gravity**: The acceleration due to gravity \( g \) at the surface of a planet is given by the formula: \[ g = \frac{G \cdot M}{R^2} \] where \( G \) is the gravitational constant, \( M \) is the mass of the planet, and \( R \) is the radius of the planet. 2. **Expressing Mass in Terms of Density**: The mass \( M \) of a planet can be expressed in terms of its density \( \rho \) and volume \( V \): \[ M = \rho \cdot V \] The volume \( V \) of a sphere (which we assume the planets are) is given by: \[ V = \frac{4}{3} \pi R^3 \] Therefore, the mass can be rewritten as: \[ M = \rho \cdot \frac{4}{3} \pi R^3 \] 3. **Substituting Mass into the Gravity Formula**: Substituting the expression for mass into the formula for \( g \): \[ g = \frac{G \cdot \left(\rho \cdot \frac{4}{3} \pi R^3\right)}{R^2} \] Simplifying this gives: \[ g = \frac{4}{3} \pi G \rho R \] This shows that the acceleration due to gravity \( g \) is directly proportional to the radius \( R \) of the planet when the density \( \rho \) is constant. 4. **Finding the Ratio of Accelerations**: Let \( R_A \) and \( R_B \) be the radii of planets A and B, respectively. Given that: \[ R_A : R_B = 3 : 1 \] We can express this as: \[ R_A = 3R \quad \text{and} \quad R_B = R \] Now, using the proportionality of \( g \) to \( R \): \[ \frac{g_A}{g_B} = \frac{R_A}{R_B} = \frac{3R}{R} = 3 \] 5. **Final Result**: Therefore, the ratio of the acceleration due to gravity at the surfaces of planets A and B is: \[ g_A : g_B = 3 : 1 \] ### Conclusion: The final answer is: \[ g_A : g_B = 3 : 1 \]
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